c++简单程序错误，跪求高手解答

Given a positive integer n and the odd integer o and the nonnegative integer p such that n = o2^p.

Example

For n = 24, o = 3 and p = 3.

Task

Write a program which for each data set:

reads a positive integer n,

computes the odd integer o and the nonnegative integer p such that n = o2^p,

writes the result.

Input
The first line of the input contains exactly one positive integer d equal to the number of data sets, 1 <= d <= 10. The data sets follow.

Each data set consists of exactly one line containing exactly one integer n, 1 <= n <= 10^6.

Output
The output should consists of exactly d lines, one line for each data set.

Line i, 1 <= i <= d, corresponds to the i-th input and should contain two integers o and p separated by a single space such that n = o2^p.

Sample Input

1
24

Sample Output

3 3

小意思，你自己粗心而已，在main函数中尼的for循环没有跳出来而且没有实际意义，改为这样就可以了，你的算法思想还是没有错的，以后要小心，做算法更是！
int main()
{
int c,n,i,x,t;
cin>>c;
while(c--)
{
cin>>n;
x=0;
i=0;
while(x<=n)
{
//for(i=0;;i++){}

x=f(i);
i++;
}
t=i-1;
for(i=t;i>=0;i--)
if(n%f(i)==0)
{cout<<n/f(i)<<' '<<i<<endl;break;}
}
return 0;
}

while(x<=n)
{
for(i=0;;i++)
x=f(i);
}
改一下

int i=0;
while(x<=n)
{
x=f(i);++i;
}

不能跳出
for(i=0;;i++)
x=f(i);循环

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