√6+√2/√6-√2=2+√3

来源：百度知道编辑：UC知道时间：2024/05/05 16:59:24

怎么得来的，基础较差，请写出过程谢谢

(√6+√2)/(√6-√2)
=(√6+√2)*(√6+√2)/(√6-√2)(√6+√2)
= (6+2+2√12)/4
=(8+4√3)/4
=2+√3

√N=N*N

自己算算

(√6+√2)/(√6-√2)
分子分母都乘以（√6+√2）
得(8+4√3)/4
约分得
2+√3

分式上下同乘以√6+√2
得（√6+√2）的平方/(√6-√2)(√6+√2)
=(8+4√3)/4
=2+√3

√6+√2/√6-√2=(√6+√2)^2/(√6-√2)*(√6+√2)
=(6+2*√12+2)/(6-2)
=(8+2*√12)/4
=(8+4*√3)/4
=2+√3