谁能帮我编个程序啊

来源：百度知道 编辑：UC知道 时间：2024/06/06 17:03:23
Write a program that requests two real numbers and a character to return the result
corresponding to one of the four arithmetic operators (+, -, *, and /) applied to the
given two real numbers. The character + corresponds to the usual arithmetic addition,
- for the subtraction, * for the multiplication, and / for the division. Any other character
will be considered as representing the arithmetic addition. We will not take into
account the risk of dividing by zero.

#include<iostream>
using namespace std;
int main(void)
{
double a,b;
char c;
while(cin>>a>>b>>c)
{
if(c=='-')
cout<<a-b;
if(c=='*')
cout<<a*b;
if(c=='/')
{
if(b!=0)
cout<<a/b;
else
cout<<"Number cannot be divided by zero";
}
if(c!='-'&&c!='*'&&c!='/')
cout<<a+b;

cout<<endl;

}
return 0;
}
测试结果：
输入：1 2 /
输出：0.5
输入：3 4 *
输出：12
输入：1 0 /
输出：Number cannot be divided by zero
。。。。