帮我做两道数学题，感谢！！！！！！！20分！！！②⑩分11111

来源：百度知道编辑：UC知道时间：2024/09/23 23:18:26

①(-2)^3＋3×(-1)^2-(-1)^4

②-1^100-(1-0.5)×3分之1×[3-(-3)^2]

要脱式过程,真的很感谢!

①(-2)^3＋3×(-1)^2-(-1)^4
=-8+3×1-1
=-8+3-1
=-5-1
=-6

②-1^100-(1-0.5)×3分之1×[3-(-3)^2]
=-1-0.5×(1/3)×(3-9)
=-1-(1/2)×(1/3)×(-6)
=-1-(1/6)×(-6)
=-1+1
=0

①(-2)^3＋3×(-1)^2-(-1)^4
=-8+3-1
=-6

②-1^100-(1-0.5)×3分之1×[3-(-3)^2]
=-1-1/2*1/3*(-6)
=-1+1
=0

① -2^3+ 3 * 1^2 - 1^4
=-8+3-1
=-6

② -1-0.5*3分之1*[3-3^2]
=-1-0.5*3分之1*(-6)
=-1-0.5*(-2)
=-1+1
=0

(-2)^3＋3×(-1)^2-(-1)^4
=-8+3×1-1
=-8+3-1
=-5-1
=-6-1^100-(1-0.5)×3分之1×[3-(-3)^2]
=-1-0.5×(1/3)×(3-9)
=-1-(1/2)×(1/3)×(-6)
=-1-(1/6)×(-6)
=-1+1
=0