一个物理问题!!!英文版的

来源：百度知道 编辑：UC知道 时间：2024/05/27 11:08:18
In the photon picture of radiation, show that if beams of radiation of two different wavelengths are to have the same intensity (or energy density) then the numbers of the photons per unit cross-sectional areas per sec in the beams are in the same ratio as the
wavelength.请详细一点证明下了,拜托大家

Etot=nhf（f is frequecy, h is planck constant.）

f=c/λ （c is the speed of the light and λ is wavelenth）

so Etot=nhc/λ

As the question told
E1=E2
hence
n1*hc/λ1=n2*hc/λ2

as h*c is constant
cancel out we get

n1/λ1=n2/λ2

rearrange
n1/n2=λ1/λ2

光子辐射的时候，两种不同的波长的波如果是相同的强度（或者能量密度），那么在每个代表性的区域在光波中光子的数量，就像波长一样有相同的比率，

供参考