Linux 简单Shell脚本编程

echo "**cmd menu**"
echo "1----date"
echo "2----ls"
echo "3----who"
echo "4----pwd"

echo "choice::"
read number
if [ 1 == $number ];then
date;
if [ 2 == #number ]; then
ls;
if [ 3 == $number ];then
who;
if [ 4 == #number ]; then
pwd;

else
echo "you are wrong"
fi

这个程序我没有调试，只是给你个思路，你可以按照我的这个框架，自己调试一下，希望能帮到 你，谢谢！

调试完毕:
#!/bin/sh
until
echo date..........1
echo ls............2
echo who...........3
echo pwd...........4
echo exit..........5
echo Please input your choice:
read choice
test $choice = 5
do
case $choice in
1) date;;
2) echo Enter target directory
read dir
ls $dir
;;
3) who
;;
4) pwd;;