微积分interval

来源:百度知道 编辑:UC知道 时间:2024/06/21 23:10:48
Consider the equation below. (Round the answers to three decimal places. If you need to use - or , enter -INFINITY or INFINITY.)

f(x) = e^3x + e^-x
(a) Find the interval on which f is increasing.

Find the interval on which f is decreasing.

(b) Find the local minimum value of f.

(c) Find the interval on which f is concave up.

(a) Take the derivative of f(x)
f'(x)=3e^3x - e^-x > 0
3e^3x > e^-x
e^-x (3e^4x-1) >0
e^4x > 1/3
4x> -ln3
x> -1/4 ln 3
(-1/4 ln 3, Infinity) f is increasing

(negative infinity, -1/4 ln 3) f is monotonically decreasing.

(b) f(-1/4 ln 3)= 3^(-3/4)+3^(1/4) = 4* 3^(-3/4)

(c) take the second order derivative of f(x)
f''(x)= 9e^3x + e^-x > 0 for all x
thus the interval is all real numbers R, namely (negative infinity, infinity)