UC知道有关生产者和消费者的问题，请高手指点...
来源：百度知道 编辑：UC知道 时间：2024/06/17 07:19:40
自己写了下简单的但是运行后，消费者总是提前消费一个，不知为什么,代码如下：public class Main {
public static void main(String[] args) {
Container con = new Container();
Producer p = new Producer(con);
Consumer c = new Consumer(con);
new Thread(p).start();
new Thread(c).start();
}
}
class Bread {
private int id;
public Bread(int id){
this.id = id;
}
public String toString(){
return "id = " + id;
}
}
class Container {
Bread bread[] = new Bread[10];
int index = 0;
public synchronized void push(Bread b){
if(index == bread.length){
try {
wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
notify();
bread[index] = b;
index++;
}
public synchronized Bread pop(){
if(index == 0){
try {
public static void main(String[] args) {
Container con = new Container();
Producer p = new Producer(con);
Consumer c = new Consumer(con);
new Thread(p).start();
new Thread(c).start();
}
}
class Bread {
private int id;
public Bread(int id){
this.id = id;
}
public String toString(){
return "id = " + id;
}
}
class Container {
Bread bread[] = new Bread[10];
int index = 0;
public synchronized void push(Bread b){
if(index == bread.length){
try {
wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
notify();
bread[index] = b;
index++;
}
public synchronized Bread pop(){
if(index == 0){
try {
这是一个同步设计的问题：
public void run() {
for(int i=0;i<20;i++){
Bread b = new Bread(i);
con.push(b);
//当i==4时候，此时b（id == 4）已经被放入到Container里面，但是在System。out。println还没有被调用的时候，consumer：：run插入在这里执行，于是出现了所示的结果。
System.out.println("我放进去了 " + b + " breads");
}