如何用C语言实现输入1个5位以内的正整数 分别输出每位数

方法1：

main( )
{
long a,b,c,d,e,x;
scanf("%ld",&x);
a=x/10000;/*分解出万位*/
b=x%10000/1000;/*分解出千位*/
c=x%1000/100;/*分解出百位*/
d=x%100/10;/*分解出十位*/
e=x%10;/*分解出个位*/
if (a!=0) printf("there are 5, %ld %ld %ld %ld %ld ",e,d,c,b,a);
else if (b!=0) printf("there are 4, %ld %ld %ld %ld ",e,d,c,b);
else if (c!=0) printf(" there are 3,%ld %ld %ld ",e,d,c);
else if (d!=0) printf("there are 2, %ld %ld ",e,d);
else if (e!=0) printf(" there are 1,%ld ",e);
}

方法2：
main()
{
int a,b,i,j,n=1,t,s[6];
scanf("%d",&a);
b=a;
while(b/10>0)
{
n++;
b=b/10;
}
for(i=n;i>=1;i--)
{
t=1;
for(j=1;j<n;j++)
{t=t*10;}
s[i]=a/t;
}
for(i=1;i<=n-1;i++)
s[i]=s[i]-s[i-1]*10;
printf("%d",s[i]);
}

欢迎经常探讨此类问题!

方法1: