数学题，，，很简单的，，但我要过程

1/2+1/4+1/8+1/16+1/32+1/64
=1/2+1/4+1/8+1/16+1/32+1/64+1/64-1/64
=1/2+1/4+1/8+1/16+1/32+1/32-1/64
=……
=1-1/64
=63/64

1/2+1/4+1/8+1/16+1/32+1/64
=32/64+16/64+8/64+4/64+2/64+1/64
=63/64

1/2=1-1/2
1/2+1/4=1-1/4
1/2+1/4+1/8=1-1/8
以此类推
原式=1-1/64=63/64

因为等式成等比数列,每后一项是前一项的二分之一
根据等比数列的公式得
1/2+1/4+1/8+1/16+1/32+1/64
=1/2乘以[1-(1/2)的6次方]再除以(1-1/2)
=1-(1/2)的6次方
=63/64