高手请进:这段代码xmlhttp代码应该怎么写?

来源：百度知道 编辑：UC知道 时间：2024/05/21 18:01:38
我希望用xmlhttp检测line.asp查看用户是否正确,确认正确后再用xmlhttp返回line2.asp中读出的数据库内容,下面这段代码应该怎么改:

showRoles(obj)
var http_request = false;
var processRequest=false;
function send_request(url) {
http_request = false;
if(window.XMLHttpRequest) {
http_request = new XMLHttpRequest();
if (http_request.overrideMimeType) {
http_request.overrideMimeType("text/xml");
}
}
else if (window.ActiveXObject) {
try {
http_request = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try {
http_request = new ActiveXObject("Microsoft.XMLHTTP");
} catch (ei) {}

showRoles(obj)
var http_request = false;
var processRequest=false;
function send_request(url) {
http_request = false;
if(window.XMLHttpRequest) {
http_request = new XMLHttpRequest();
if (http_request.overrideMimeType) {
http_request.overrideMimeType("text/xml");
}
}
else if (window.ActiveXObject) {
try {
http_request = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try {
http_request = new ActiveXObject("Microsoft.XMLHTTP");
} catch (ei) {}
}
}
if (!http_request) {
window.alert(" 不能创建对象.");
return false;
}
http_request.onreadystatechange = processRequest;

http_request.open("GET",url, true);

http_request.send(null);
}
function processRequest() {
if (http_request.readyState == 4) {
if (http_request.status == 200) {
http_request.ResponseT