今晚作业:急求因式分解答案!

(1)4ab-3ac+8b-6c
=a[4b-3c]+2[4b-3c]
=[4b-3c][a+2]

(2)ab-5bc-2a^2+10ac=
=b[a-5c]-2a[a-5c]
=[a-5c][b-2a]

(3)x^3-2x^2+2x-1=
=[x^3-1]-2x[x-1]
=[x-1][x^2+x+1]-2x[x-1]
=[x-1][x^2+x+1-2x]
=[x-1][x^2-x+1]

(4)x^2-y^2-z^2-2yz=
=x^2-[y^2+2yz+z^2]
=x^2-[y+z]^2
=[x+y+z][x-y-z]

(5)a^3+a^2+b^3+b^2+2ab=
=[a^3+b^3]+[a^2+2ab+b^2]
=[a+b][a^2-ab+b^2]+[a+b]^2
=[a+b][a^2-ab+b^2+a+b]

(6)1+(a+b)+(a+b)^2+(a+b)^3=
=[1+(a+b)]+(a+b)^2[1+(a+b)]
=[1+(a+b)][1+(a+b)^2]
=[1+a+b][1+a^2+2ab+b^2]

（1） a(4b-3c)+2(4b-3c)=(a+2)(4b-3c)

(2) a(b-2a)-5c(b-2a)=(a-5c)(b-2a)

(3) x^3-x^2-x^2+2x-1=x^2(x-1)-(x-1)^2=(x^2-1)(x-1)
= (x-1)^2(x+1)

(4) x^2-(y^2+2yz+z^2)=x^2－(y+z)^2=(x-y-z)(x+y+z)

(5) a^3+b^3+a^2+b^2+2ab=(a+b)(a^2+ab+b^2)(a+b)^2
=(a+b)(a^2-ab+b^2+a+b)