编程计算由下列公式确定的S值,

(1)S=1(平方)+2(平方)+3(平方)+...+n(平方)
(2)S=1*2(平方)*3(3次方)+*…*n(n次方)
(3)S=1+1*2+1*2*3+…+1*2*3*…*n
(4)s=1-1/3+1/5-1/7+1/9-…+(-1)(n+1次方)1/2n-1

(1)S=1^2+2^2+3^2+4^2+...+n^2
(2)S=1*2^2*3^3*4^4.....*n^n
(3)
dim n as integr,S As long
n=text1.text
S=1
for t=1 to n
S=S+S*t
next t
(4)
dim n as integr,S As long
n=text1.text
S=1
for t=1 to n
S=S+(-1)^(n+1)*1/(2n-1)
next t

啥语言？。。。。都不说清楚

c语言版(1)#include"iostream.h"
int s=0;
void main()
{
scanf("%d",&n);
for(int i=0;i<n;i++)
{
s+=(n+1)*(n+1);
}
printf("%d",s);
}
(2)#include"iostream.h"
int s=0;
int ndencifang(int n);
void main()
{
scanf("%d",&n);
for(int i=0;i<n;i++)
{
s+=ndencifang(i+1);
}
printf("%d",s);
}
int ndencifang(int n)
{
int s=1
for(i