UC知道下面这段javascript代码哪错了?
来源：百度知道 编辑：UC知道 时间：2024/05/29 02:26:15
下面这段javascript代码哪错了?为什么点链接的时候不能弹出新页面,而且总是显示网页上有错误!新打开的窗口希望窗口最大化!
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312">
<title>无标题文档</title>
</head>
<script language="javascript">
function info()
{
newwindow=window.open("index.asp","fullscreen=3");
}
</script>
<body>
<p onClick="info()">a</p>
<p onClick="info()">b</p>
<p onClick="info()">c</p>
</body>
</html>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312">
<title>无标题文档</title>
</head>
<script language="javascript">
function info()
{
newwindow=window.open("index.asp","fullscreen=3");
}
</script>
<body>
<p onClick="info()">a</p>
<p onClick="info()">b</p>
<p onClick="info()">c</p>
</body>
</html>
newwindow=window.open("index.asp","","fullscreen=3");
newwindow=window.open("index.asp","fullscreen=3");
fullscreen=3是什么参数
你要是想打开一个弹窗.
就把这样写
<script language="javascript">
function info()
{
window.open('index.asp','弹出窗口的名称');
}
</script>
或者
<p onClick="window.open('index.asp','弹出窗口的名称');">a</p>