◆◇高悬赏!100分◆◇◆◇vb中如何快速旋转图片◆◇◆◇◆◇

来源：百度知道 编辑：UC知道 时间：2024/06/25 16:40:23
必须要快速,旋转图片框里的图片,回答请详细!

以下方法不行,太慢!
Dim x As Integer, y As Integer
Dim X1 As Integer, Y1 As Integer
Dim X2 As Double, Y2 As Double
Dim X3 As Double, Y3 As Double
Dim HuDu As Double
' JiaoDu角 度
HuDu = JiaoDu * Pi / 180 ' 弧 度
PicSource.ScaleMode = vbPixels
PicTarget.ScaleMode = vbPixels
For x = 0 To PicTarget.ScaleWidth
X1 = x - PicTarget.ScaleWidth \ 2
For y = 0 To PicTarget.ScaleHeight
Y1 = y - PicTarget.ScaleHeight \ 2
X2 = X1 * Cos(-HuDu) + Y1 * Sin(-HuDu)
Y2 = Y1 * Cos(-HuDu) - X1 * Sin(-HuDu)
X3 = X2 + PicSource.ScaleWidth \ 2
Y3 = Y2 + PicSource.ScaleHeight \ 2
If X3 > 0 And X3 < PicSource.ScaleWidth - 1 And Y3 > 0 And Y3 < PicSource.ScaleHeight - 1 Then
PicTarget.PSet (x, y), PicSource.

启动vb6建立一个标准exe工程，首先添加两个图片框（picture1和picture2），添加三个命令按钮command1（caption=“正常显示”）、command2（caption=“180度倒立”）、command3（caption=“45度旋转”），双击窗体，写入以下代码：
PrivateConstSRCCOPY=&HCC0020
PrivateConstPi=3.14

PrivateDeclareFunctionSetPixelLib"gdi32"(ByValhdcAsLong, ByValxAsLong,ByValyAsLong,ByValcrColorAsLong)AsLong
PrivateDeclareFunctionGetPixelLib"gdi32"(ByValhdcAsLong, ByValxAsLong,ByValyAsLong)AsLong

PrivateDeclareFunctionStretchBltLib"gdi32"(ByValhdcAsLong, ByValxAsLong,ByValyAsLong,ByValnWidthAsLong,ByValnHeightAsLong, ByValhSrcDCAsLong,ByValxSrcAsLong,ByValySrcAsLong,ByValnSrcWidth AsLong,ByValnSrcHeightAsLong,ByValdwRopAsLong)AsLong

privateSubbmp_rotate(pic1AsPictureBox,pic2AsPictureBox,ByValtheta)‘45度旋转
Dimc1xAsInteger,c1yAsInteger
Dimc2xAsInteger,c2yAsInteger
DimaAsSingle
Dimp1xAsInteger,p1yAsInteger
Dimp2xAsInteger,p2yAsInteger
DimnAsInteger,rAsInteger

c1