1+1\2+1\4+……
来源:百度知道 编辑:UC知道 时间:2024/05/24 20:22:40
1+1\2+1\4+1\8+1\16+……+1\2^n=?
1+1\2+1\4+1\8+1\16+……=?
对不起弄错了
1+1\2+1\4+1\8+1\16+……=?
对不起弄错了
=1+1-1/2+1/2-1/4+......+1/2^(n-1)-1/2^n
=2-1/2^n
=(2*2^n-1)/2^n
给个高等数学的解法,呵呵
=lim(1-(1/2)^(n+1))/(1/2) n->无穷
=2
1/2+1/4+1/8+1/16+……+1/2^n……
设1/2+1/4+1/8+1/16+……+1/2^n……=a,
因为此为无限收敛级数,
所以2a=1+1/2+1/4+1/8+1/16+……+1/2^n……,
而a=2a-a=1+1/2+1/4+1/8+1/16+……+1/2^n……-(1/2+1/4+1/8+1/16+……+1/2^n……)=1
(1-1\2004)(1-1\2003)(1-1\2002).........(1-1\3)(1-1\2)
(1+1\2)*(1+1\3)*(1+1\3)*(1+1\4)*......(1+1\20)
(1\2+1\3+...+1\2006)(1+1\2+1\3+...+1\2005)-(1+1\2+1\3+...+1\2006)(1\2+1\3+...+1\2005)
((1+1\2)(1+1\3)(1+1\4)(1+1\5)------(1+1\100))\(1-1\2)(1-1\3)(1-1\4)------(1-1\100)
((1+1\2)(1+1\3)(1+1\4)(1+1\5)------(1+1\100))\(1-1\2)(1-1\3)(1-1\4)------(1-1\100)等多少
1\2+1\4+1\8+...+1\256+1\512+1\1024=??
(1-1\2)+(1\2-1\3)+(1\3-1\4)+(1\4-1\5)+(1\5-1\6)+........(1\2005-1\2006
(1-1\2)+(1\2-1\3)+(1\3-1\4)+(1\4-1\5)+(1\5-1\6)+........(1\2005-1\20把括号变为绝对号咋么做06
[1+(-1\2)]+[1\2+(-1\3)]+[1\3+(-1\4)]+......[1\1999+(-1\2000)]
3\1 3\1 3\1 3\1 3\1 =9\2