编制一个程序,从键盘输入年和月,计算并输出这一年的这一月共有多少天.

#include <stdio.h>

const int daysOfMonth[] ={31,28,31,30,31,30,31,31,30,31,30,31};
int isLeapYear(int year);
int main(void)
{
int y,m;
int days;
scanf("%d %d",&y,&m);
if(isLeapYear(y) && m == 2)
days = 29;
else
days = daysOfMonth[m-1];
printf("days=%d\n",days);
return 0;
}

int isLeapYear(int year)
{
int leap = 0;
if(year%100 == 0 && year%400 ==0)
leap = 1;
else if(year%100 != 0 &&year%4 ==0)
leap = 1;
return leap;
}

'用VBS写的
do until yesno=vbyes
riqi=date:riqi=left(date,instrrev(date,"-")-1):criqi=replace(riqi,"-","年")
n=inputbox("请输入年份和月份" & vbcrlf & "例如：" & criqi & "输入","提示",riqi)
m=month(n)
if m<12 then
zhrq=left(n,instr(n,"-")) & m+1 & "-1"
else
zhrq=left(n,instr(n,