ycosx+sin(x-y)=0
来源:百度知道 编辑:UC知道 时间:2024/05/26 19:25:54
求由方程ycosx+sin(x-y)=0确定的隐函数y=f(x)的导数y`
要写出过程.
要写出过程.
由方程ycosx+sin(x-y)=0
对这个方程进行x求导,
即有:y'*cosx-y*sinx+cos(x-y)*(1-y')=0
这样对它进行化简得
y'=[y*sinx-cos(x-y)]/[cosx-cos(x-y)]
我来试试:
y'cosx-ysinx+cos(x-y)(1-y')=0
y'cosx-ysinx+cos(x-y)-cos(x-y)y'=0
[cosx-cos(x-y)]y'=ysinx-cos(x-y)
ycosx+sin(x-y)=0
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