Ajax发送XML的问题

来源:百度知道 编辑:UC知道 时间:2024/05/04 07:23:53
各位大哥.小弟在此想请问一下,ASP页面如何接收Ajax发送的XML文档的?又是如果返回XML的文档给Ajax的?哪位大哥可以给个源代码看看阿?小弟在此感激不尽阿.

function callServer() {
var firstName = document.getElementById("firstName").value;
var lastName = document.getElementById("lastName").value;
var street = document.getElementById("street").value;
var city = document.getElementById("city").value;
var state = document.getElementById("state").value;
var zipCode = document.getElementById("zipCode").value;

var xmlString = "<profile>" +
" <firstName>" + escape(firstName) + "</firstName>" +
" <lastName>" + escape(lastName) + "</lastName>" +
" <street>" + escape(street) + "</street>" +
" <city>" + escape(city) + "</city>" +
" <state>&quo

改成这样的:
var xmlString = "<? xml version=\"1.0\" ?><profile>" +
" <firstName>" + escape(firstName) + "</firstName>" +
" <lastName>" + escape(lastName) + "</lastName>" +
" <street>" + escape(street) + "</street>" +
" <city>" + escape(city) + "</city>" +
" <state>" + escape(state) + "</state>" +
" <zip-code>" + escape(zipCode) + "</zip-code>" +
"</profile>";

xmlhttp.send("xml="+xmlString);

发送后功后,在后台接收的时候用:
request["xml"].
还有不懂的,Q我:5171031