怎么用MATLAB求解方程组
来源:百度知道 编辑:UC知道 时间:2024/05/17 22:27:04
用MATLAB求出系数a ,b ,c
1286.05=35a+1120b+39410c
33264.45=1120a+39410b+1489600c
887496.99=39410a+1489600b+59288978c
1286.05=35a+1120b+39410c
33264.45=1120a+39410b+1489600c
887496.99=39410a+1489600b+59288978c
我解释吧,这个倒不清楚,显然正确有``
>> syms a b c
>> [a,b,c]=solve('1286.05=35*a+1120*b+39410*c ','33264.45=1120*a+39410*b+1489600*c','887496.99=39410*a+1489600*b+59288978*c','a,b,c')
得到结果
a =
-69.231167317049669990846461434697
b =
10.055005987653046476575888340594
c =
-.19163831134419369713487360546184
直接解法
A=[35,1120,39410;1120,39410,1489600;39410,1489600,59288978];
b=[1286.05,33264.45,887496.99];
x=A/b;
x的三个数就是a,b,c