编一个链表，十个节点

#include <iostream>
using namespace std;
struct list
{
int data;
list *p;
};

void main()
{
list *list1=new list(),*now=list1;
int i(0);
do{
now->data=i;
i++;
now->p=new list();
now=now->p;
}while(i<10);
now=list1;
for (i=0;i<10;i++)
{
cout<<now->data;
now=now->p;
}

}

#include <iostream>
using namespace std;
struct list
{
int data;
list *p;
};

void main()
{
list *list1=new list(),*now=list1;
int i(0);
do{
now->data=i;
i++;
now->p=new list();
now=now->p;
}while(i<10);
now=list1;
for (i=0;i<10;i++)
{
cout<<now->data;
now=now->p;
}

}
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楼上的答案有问题,最后一个接