使用配方法的8年级方程

(x-1/2)^2=5/4
(x-5/4)^2=17/16
(2x-1/2)^2=5/4

解：
1.(x-1/2)^2-5/4=0
(x-1/2+√5/2)(x-1/2-√5/2)=0
x=1/2±√5/2

2.2(x-5/4)^2-9/16=0
2(x-1/5+3√2/4)(x-1/5-3√2/4)=0
x=1/5±3√2/4

3.(2x-1/2)^2-5/4=0
(2x-1/2+√5/2)(2x-1/2-√5/2)=0
x=1/4±√5/4

解毕

x^2-x-1=0
(x^2-x+1/4)-1-1/4=0
(x-1/2)^2=5/4,
x=√5/2+1/2,x=-√5/2+1/2,
2x^2-5x+1=0 ,
2(x^2-5x/2+25/16)+1-25/8=0
(x-5/4)^2=17/16,
x=√17/4+5/4,x=-√17/4+5/4
4x^2-2x-1=0
4(x^2-x/2+1/16)-1-1/4=0
(x-1/4)^2=5/16
x=√5/4+1/4,x=-√5/4+1/4