请帮助解决问题:1/(1×2)+1/(2×3)+1/(3×4)+1/(4×5)+ .......1/(2003×2004)=?

来源:百度知道 编辑:UC知道 时间:2024/05/25 11:18:13

1/(1×2)+1/(2×3)+1/(3×4)+1/(4×5).......1/(2003×2004)
=(1-1/2)+(1/2-1/3)+(1/3-1/4)+(1/4-1/5).........(1/2003-1/2004)
=1-1/2004
OVER

2003/2004
1/(1×2)=1-1/2
1/(2X3)=1/2-1/3
最后是1-1/2004=2003/2004

1/n(n+1)=1/n-1/(n+1)
1/1(1+1)=1/1-1/2
1/2(2+1)=1/2-1/3
1/3(3+1)=1/3-1/4
.........
.........
1/2003(2003+1)=1/2003-1/2004
左右相加就得到
1/(1×2)+1/(2×3)+1/(3×4)+1/(4×5)+ .......1/(2003×2004)=1/1-1/2004=2003/2004