UC知道翻译一下这句话阿，大虾救命！！！
来源：百度知道 编辑：UC知道 时间：2024/05/27 04:18:44
解释一下后面的问题就可以了
N square frames (1 ≤ N ≤ 15) were sequentially drawn on screen 50 characters wide 20 lines tall. If parts of some frames intersect, only the part of the frame drawn latter remains visible. Each frame lies fully on the screen.
You need to write a program that builds a possible sequence of frames that (if drawn sequentially) would produce the same picture on the screen. Your sequence does not have to be the same with the original sequence used to build the picture on the screen. However, it should not contain more than 2000 frames.
我只是想问，为什么全面他说n square frames(1<=n<=15)，后来又说not more than 2000frames，不是矛盾了吗？？而且，长50款20的点阵如何放进去2000个frames啊？？
N square frames (1 ≤ N ≤ 15) were sequentially drawn on screen 50 characters wide 20 lines tall. If parts of some frames intersect, only the part of the frame drawn latter remains visible. Each frame lies fully on the screen.
You need to write a program that builds a possible sequence of frames that (if drawn sequentially) would produce the same picture on the screen. Your sequence does not have to be the same with the original sequence used to build the picture on the screen. However, it should not contain more than 2000 frames.
我只是想问，为什么全面他说n square frames(1<=n<=15)，后来又说not more than 2000frames，不是矛盾了吗？？而且，长50款20的点阵如何放进去2000个frames啊？？
N 次方的桢图象(1<=N<=15),被依序画在50 字节宽,20 行高的屏幕上.如果某些桢图象交叉,仅仅该桢的后一部分保持可见.每个桢全水平地显现在屏幕上.
你需要写一个程序,建立一可能的桢序列;这样,(如果画面是连续的)就会屏幕上产生一相同的画面.你建立的序列,不必与在屏幕建立该画面所用的原序列相同.但是,它不应多于2,000 桢.
(不矛盾: 从上述译文中可理解,它的N 次方不应大于 2,000桢)
它说可以重叠撒。。。
N 方形的框架(1 ≤ N ≤ 15) 宽连续地被画了在屏幕50 字符20 条线高。如果一些框架的部份相交, 只有框架被画的后者遗骸的部份可看见。各个框架充分地说谎在屏幕。
您需要写建立框架一个可能的序列的节目(如果连续地画) 会导致同样图片在屏幕。您的序列不必须是同样以原始的序列使用建立图片在屏幕。但是, 它不应该包含超过2000 个框架。