计算(x-1)(x-2)(x-3)(x-4)
来源:百度知道 编辑:UC知道 时间:2024/05/14 12:28:29
适合初二年级,越简单越好,要过程!
原式=(x-1)(x-4)(x-2)(x-3)
=(x^2-5x+4)(x^2-5x+6)
=x^4-5x^3+6x^2-5x^3+25x^2-30x+4x^2-20x+24
=x^4-10x^3+35x^2-50x+24
等于什么?因式分解的话这就是答案。
原式=(x-1)(x-4)(x-2)(x-3)
=(x^2-5x+4)(x^2-5x+6)
=(x^2-5x)^2+10(x^2-5x)+24
接下来自己算吧
原式=(x-1)(x-4)(x-2)(x-3)
=(x^2-5x+4)(x^2-5x+6)
=(x^2-5x)^2+10(x^2-5x)+24
(x-1)(x-2)(x-3)(x-4)
=[(x-1)(x-4)][(x-2)(x-3)]
=(x^2-5x+4)(x^2-5x+6)
=[(x^2-5x+5)-1][(x^2-5x+5)+1]
=(x^2-5x+5)^2-1^2
=x^4+25x^2+25-10x^3+10x^2-50x-1
=x^4-10x^3+35x^2-50x+24.
(x-1)(x-2)(x-3)(x-4)
=[(x-1)(x-4)][(x-2)(x-3)]
=(x^2-5x+4)(x^2-5x+6)
=[(x^2-5x+5)-1][(x^2-5x+5)+1]
=(x^2-5x+5)^2-1^2
=x^4+25x^2+25-10x^3+10x^2-50x-1
=x^4-10x^3+35x^2-50x+24.
(x^?是x的?次方)
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