JS 无法调用的问题

来源：百度知道 编辑：UC知道 时间：2024/05/22 13:13:13
<script language=JavaScript>
function PageMove(name){
alert("abc");

if (name.equals("Firstpage"){
location.href="/Show.do?Check='Firstpage'";
}else if(name.equals("pageUp"){
location.href="/Show.do?Check='pageUp'";
}else if(name.equals("pageDown"){
location.href="/Show.do?Check='pageDown'";
}else if(name.equals("Lastpage"){
location.href="/Show.do?Check='Lastpage'";
}
}
</script>
<input type="button" name="Firstpage" value="Firstpage" onclick="PageMove('Firstpage')">
<input type="button" name="pageUp" value="pageUp" onclick="PageMove('pageUp')">
<input type="button" name="pageDo

你的意思是不是点击pageup页面跳转到：/show.do?check=pageup;点击lastpage页面执行/show.do?check=lastpage ？
如果是这样的话，根本不需要这么麻烦，直接获取传递的值就可以了：

<script language=JavaScript>
function PageMove(name){
alert("abc");
location.href="/Show.do?Check="+name+"";
}
</script>
<input type="button" name="Firstpage" value="Firstpage" onclick="PageMove('Firstpage')">
<input type="button" name="pageUp" value="pageUp" onclick="PageMove('pageUp')">
<input type="button" name="pageDown" value="pageDown" onclick="PageMove('pageDown')">
<input type="button" name="Lastpage" value="Lastpage" onclick="PageMove('Lastpage')">