c#来修改XML文档中某个接点的值

来源:百度知道 编辑:UC知道 时间:2024/05/17 20:56:14
我要将XML中某个接点查询出来(接点没有属性和子接点),并将起的值修改后保存.

XmlDocument doc = new XmlDocument();
doc.load("c:\\a.xml");
XmlNode node = doc.selectSingleNode("root");
node.firstChild.value = "aaaa";
doc.save("c:\\a.xml");

using System;
using System.Collections;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Web;
using System.Web.SessionState;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.UI.HtmlControls;
using System.Xml ;
namespace DataGridTest
{
/// <summary>
/// XML 的摘要说明。
/// </summary>
public class XML : System.Web.UI.Page
{
protected System.Web.UI.WebControls.Button btadd;
protected System.Web.UI.WebControls.Button btedit;
protected System.Web.UI.WebControls.Button btdelete;
protected System.Web.UI.WebControls.Button btselect;
private XmlDocument xmldoc; <