UC知道aboutlog
来源：百度知道 编辑：UC知道 时间：2024/06/01 06:12:19
/x-4y/+（2y—1)^2=0,求log2(y/x)的值
2lg[(x-y)/2]=lgx+lgy,求x/y的值
lg[3(x^3)]-lg[3(y^3)]=9,求x/y
log2(x)+log2(y)=0,x^4+y^4=194,求log2(x+y)值
2lg[(x-y)/2]=lgx+lgy,求x/y的值
lg[3(x^3)]-lg[3(y^3)]=9,求x/y
log2(x)+log2(y)=0,x^4+y^4=194,求log2(x+y)值
-2
2
1000
2
1. /x-4y/+（2y—1)^2=0,==>x=4y, 2y-1=0=>x=2,y=1/2
log2(y/x)= log2(1/4)= -2
2. 2lg[(x-y)/2]=lgx+lgy=lgxy,
[(x-y)/2]^2=xy, x^2+y^2-6xy=0
(x/y)^2+1-6x/y=0
x/y =2。（-3舍）
3. lg[3(x^3)]-lg[3(y^3)]=9,
lg[3(x^3)/3(y^3)]=9=lg10^9
(x/y)^3 =10^9
x/y=10^3=1000
4. log2(x)+log2(y)=0==>log2(xy)=0==>xy=1
x^4+y^4=194,==>(x^2+y^2)^2-2x^2y^2=194
==>x^2+y^2=14=(x+y)^2-2xy
==>x+y=4
log2(x+y)=log2(4)=2