(x-4)(x-2)-(x-1)(x+3),其中x=-2/5
来源:百度知道 编辑:UC知道 时间:2024/05/15 00:31:24
过程
(x-4)(x-2)-(x-1)(x+3),其中x=-2/5
(x-4)(x-2)-(x-1)(x+3)=x2-6x+8-x2-2x+3
=-8x+11
当x=-2/5时
原式=-8×(-2/5)+11=16/5+11=14.2
把x带进去不得了?
(x-4)(x-2)-(x-1)(x+3)
=(-2/5-4)(-2/5-2)-(-2/5-1)(-2/5+3)
=-22/5*-12/5-(-7/5*13/5)
=(22*12+7*13)/5
=(264+91)/5
=355/5
=71
把x带进去不得了?
(x-4)(x-2)-(x-1)(x+3)
=(-2/5-4)(-2/5-2)-(-2/5-1)(-2/5+3)
=-22/5*-12/5-(-7/5*13/5)
=(22*12+7*13)/5
=(264+91)/5
=355/5
=71
(x-4)(x-2)-(x-1)(x+3)
=(X平方-6X+8)-(X平方+2X-3)
=-6X+8-2X+3
=-8X+11
把X代进去
原式=-8*-2/5+11
=71/5
(x-4)(x-2)-(x-1)(x+3),x=-2/5
(x-4)(x-2)-(x-1)(x+3)=x2-6x+8-x2-2x+3
=-8x+11
代入x=-2/5
得14.2
X*X-2X-1=0 求2x*x*x-3*x*x-4*x+2
解方程(x+1)(x+2)(x+3)(x+4)=(x+1)(x+1)+(x+2)(x+2)+(x+3)(x+3)+(x+4)(x+4)
(x+1)(x+2)(x+3)(x+4)=(x+1)(x+1)+(x+2)(x+2)+(x+3)(x+3)+(x+4)(x+4)
因式分解(X+1)(X+2)(X+3)(X+4)+1
2|x|+|x+1|--|3--x|=2x+4
(x+1)(x+2)(x+3)(x+4)-24因式分解
(X+2)(X+3)(X+4)(X+5)+1
(x+2)(x-1)(x-3)(x+4)-144
(x-1)(x-2)(X-3)(x-4)-48
计算(X-1)(X-2)(X-3)(X-4)