帮忙解答几道数学题.!今天晚上就要.!!

(1) 0.75^x+0.4375=1
0.75^x=0.5625
X=2
(2) 2^2x+3-2^2x+1=192
2^2x+1*(4-1)=192
2^2x+1=64
2X+1=6
X=2.5
(3) (-0.125)^2 × 2^7 =(0.125)^2 × 2^7= (1/8)^2 × 2^7=
=2^(-6)*2^7=2
4. (-0.5)^101 × 2^5 × 2^100 =- (1/2)^101 × 2^5 × 2^100
=-2^(-101) × 2^5 × 2^100 =-2^4=-16
5. (-a^4)^3+(-a^2)^6-a×(-a)^3 ×(-a^2)^4
=-(a^4)^3-(a^2)^4+(a^2)^6+a×a^3 ×(a^2)^4
=-a^12-a^8+a^12+a^12
=a^12-a^8这个题没出错的话就是这个答案
(-a^2)^4好像应该是(-a^3)^4答案就是0.

这么简单就不会，现在的孩子呀

我才小学啊这什么问题啊哥哥姐姐 9999啊

(1)
0.75^x+0.4375=1
(3/4)^x=9/16
:`3*3=9 4*4=16
:. x=2
(2)看不懂你写什么,或者你适当的加些括号喇～～
(3)
(-0.125)^2 × 2^7
=[(1/8)^2] * [2^7]
=[(2^-3)^2] * 2^7
=(2^-6) * 2^7
=2
(4)
[(-0.5)^101] ×[ 2^5 ]×[ 2^100 ]
=-[(1/2)^101] *[ 2^5] *[ 2^100]
=-[(2^-1)^101] * (2^5) * (2^100)
=-(-2^-101) * (2^5) * (2^100)
=-2^4
= -16
(5)
(-a^4)^3-(-a^2)^4+(-a^2)^6-a