编程，输入一行字符，以“\n”结束。分别统计出其中英文字母、空格、数字和其它字符的个数。

#include <stdio.h>
void main()
{char ch;
int alpha,space,number,another;
alpha=space=number=another=0;
printf("Enter: ");
while((ch=getchar())!='\n')
{if(ch>='a'&&ch<='z'||ch>='A'&&ch<='Z') alpha++;
else if(ch==' ') space++;
else if(ch>='0'&&ch<='9') number++;
else another++;
}
printf("alpha=%d,space=%d,number=%d,another=%d",alpha,space,number,another);
}

#include<stdio.h>
#define N 100
void main()
{ char string[N]
int i,num=0,word=0,zifu,shuzi,qita;
char c;
gets(string);
for(i=0;(c=string[i]!='\n';i++);
{
if(c>='A'&&c<='z')
zifu++;
else if(c>='a'&&c<='z')
zifu++;
else if(c>='0'&&c<='9')