能被11整除,且各位上的数字之和是43的五位整数一共有多少个?

1--97999
2--98989
3--99979
<%
n=0
for i=910 to 9090
j=11*i
a=int(j/10000)
b=int((j-10000*a)/1000)
c=int((j-10000*a-1000*b)/100)
d=int((j-10000*a-1000*b-100*c)/10)
e=j-10000*a-1000*b-100*c-10*d
m=a+b+c+d+e
if m=43 then
n=n+1
%>
<%=n%>--<%=j%><br>
<%
end if
next
%>

15 个79999 88999 89899 89989 89998
97999 98899 98989 98998 99799 99889
99898 99979 99988 99997

<script>

function overinstr(instr){
var s=instr.toString();
m=0

for(var i=0;i<s.length;i++)
{m+=parseFloat(s.substr(i,1))
}
return m;
}
var n=0
for(i=70000;i<99999;i++){if(overinstr(i)==43){n+=1;document.write(i+"<br>")}}
document.write("共"+n+"个")
</script>