1/1998+2/1998+3/1998+......1998/1998求解
来源:百度知道 编辑:UC知道 时间:2024/05/12 10:05:15
=(1+2+3+4.......+1998)/1998
=1998(1+1998)/2/1998
=1997001/1998
=999.5
1/1998+2/1998+3/1998+......1998/1998
=(1+2+...+1998)/1998
=1998*(1998+1)/(2*1998)
=1999/2
原式=1/1998×(1+2+3+4+……+1998)
=1/1998×(1+1998)×1998/2
=1/2×1999=1999/2
=(1+2+……+1998)/1998
=【(1+1998)*1998】/2/1998
=1999/2
=999.5
1/1998+2/1998+3/1998+......1998/1998=(1+2+……+1998)/1998={[(1+1998)/2]*1998}/1998=1999/2
原式=(1+2+3+……+1997)/1998+1
=[(1+1997)*1997/2]/1998+1
=1997/2+1
=999.5
1/2+1/3+1/4+......+1/1998=?
1*1-2*2+3*3-4*4+......+1997*1997-1998*1998+1999*1999
求1*1+2*2+3*3+4*4+......+1998*1998的和以及思路.谢谢!!!
计算 1又1998分之1+2又1998分之3+3又1998分之5加4又1998分之7+...........+50又1998分之99
1-2+3-4+5-6+......+1997-1998+1999
计算1/x(x+1)+1/(x+1)(x+2)…+1/(x+1998)(x+1999)
|ab-2|-(b-1)(b-1)=0时,求1/ab+1/(a+1)(b+1)+ 1/(a+2)(b+2)+……+1/(a+1998)(b+1998)
(1+1/2+1/3+1/4)×
(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)
(1-1/2^2)*(1-1/3^2)*(1-1/4^2).......(1-1/100^2)