(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)
来源:百度知道 编辑:UC知道 时间:2024/05/10 18:45:19
要过程
原式=(1-1/2)(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)*2
根据(a+b)(a-b)=a^2-b^2
所以原式=(1-1/2^2)(1+1/2^4)(1+1/2^8)*2
=(1-1/2^4)(1+1/2^8)*2
=(1-1/2^8)*2
=2-1/2^7
^着个符号是什么意思?
硬算
原式=(1-1/2)(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)*2
=(1-1/2^2)(1+1/2^2)(1+1/2^4)(1+1/2^8)*2
=(1-1/2^4)(1+1/2^4)(1+1/2^8)*2
=(1-1/2^8)(1+1/2^8)*2
=(1-1/2^8)*2
=255/128
答案应该不会有错
(1/2005-1)(1/2004-1)........(1/3-1)(1/2-1)
1+1/(1+2)+1/(1+2+3)+...+1/(1+2+3+...+100)
1+1/(1+2)+1/(1+2+3)+-------+1/(1+2+3+----+100)
1+1/1+2+1/1+2+3+...+1/1+2+3...+2000
1+1/1+2+1/1+2+3.........+1/1+2+3.....100
1*(1/1+2)*(1/1+2+3)*~~~*(1/1+2+~~~2005)=?
(1-1/2)(1-1/3)(1-1/4)(1-1/5).....(1-1/1000)
1+1/2+1+1/3+1+1/4+......+1/100=?
(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)
(1-1/2^2)*(1-1/3^2)*(1-1/4^2).......(1-1/100^2)