2(a-1)平方-12(a-1)+18

来源:百度知道 编辑:UC知道 时间:2024/05/17 02:45:15

你是要分解因式还是化简?
如果是因式分解的话
=2[(a-1)^2-6(a-1)+9]
=2(a-1-3)^2
=2(a-4)^2
如果是化简的话
=2(a^2-2a+1)-12a+12+18
=2a^2-4a+2-12a+12+18
=2a^2-16a+32

2(a-1)平方-12(a-1)+18
=[2(a-1)-6][(a-1)-3]
=(2a-8)(a-4)
=2(a-4)²

2(a-1)^2-12(a-1)+18
把a-1=x
2x^2-12x+18
2x -6
x -3(十字相乘法)
=(2x-6)(x-3)
=[2(a-1)-6][(a-1)-3]
=(2a-8)(a-4)