ab/(a-c)c =b/c+b/(a-c)

来源：百度知道 编辑：UC知道 时间：2024/06/07 02:22:51
请问这是怎么变过来的啊，请详细的解答一下

原分子ab=ab-bc+bc
=b(a-c)+bc
再分解整个分式
ab/[(a-c)c]=(ab-bc+bc)/[(a-c)c]
=[b(a-c)+bc]/
[(a-c)c]
=b(a-c)/[(a-c)c]+bc/[(a-c)c]
=b/c+b/(a-c)

通分啊
右边=b/c+b/(a-c)=[b(a-c)+bc]/c(a-c)=ab/(a-c)c=左边

ab/(a-c)c = (a -c +c)b/(a-c)c = (a-c)b/(a-c)c + cb/(a-c)c
= b/c + b/(a-c)

ab/(a-c)c=(ab-bc+bc)/(a-c)c=(ab-bc)/(a-c)c+bc/(a-c)=b/c+b/(a-c)

ab/(a-c)c =(ab-bc+bc)/(a-c)c=(ab-bc)/(a-c)c+bc/(a-c)c=
b(a-c)/(a-c)c+b/(a-c)=b/c+b/(a-c)