数学,马上要,要有过程,是初二的公因式

来源：百度知道 编辑：UC知道 时间：2024/06/06 03:42:23
1.计算用简便方法做：202的2次方-54的2次方+256乘以352
2.把下列个因式分解: (1)x(x-3)+(3-x)的2次方
(2)-3x(x+y)+(x+y)的2次方 (3)x(x+y)乘以(x-y)-x(x+y)的2次方

1. (202+54)(202-54)+256*352
=256*148+256*352
=256*(148+352)
=256*500
=128000
2.(1) x(x-3)+(3-x)的2次方
=x(x-3)+(x-3)的2次方
=(x-3)(x+x-3)
=(x-3)(2x-3)
(2) -3x(x+y)+(x+y)的2次方
=(x+y)的2次方-3x(x+y)
=(x+y)(x+y-3x)
=(x+y)(y-2x)
(3) x(x+y)乘以(x-y)-x(x+y)的2次方
=x(x的2次方-y的2次方)-x(x的2次方+2xy+y的2次方)
=x(x的2次方-y的2次方-x的2次方-2xy-y的2次方)
=x(-2y的2次方-2xy)
=-2xy(x+y)

)x(x-3)+(3-x)的2次方
(2)-3x(x+y)+(x+y)的2次方 (3)x(x+y)乘以(x-y)-x(x+y)的2次方

1.202^2-54^2+256*352=(202+54)*(202-54)+256*352
=256*148+256*352
=256*(148+352)
=256*500
=128000

2.（1）x(x-3)+(3-x)^2=(x-3)(x+x-3)=(x-3)*(2x-3)
(2) -3x(x+y)+(x+y)^2=(x+y)*(-3x+x+y)=(x+y)*(y-2x)
(3) x(x+y)*(x-y)-x(x+y)^2=x(x+y)(x-y-x-y)=-2xy(x+y)