1*3/1+3*5/1+5*7/1....99*101/1=??的简便运算
来源:百度知道 编辑:UC知道 时间:2024/05/10 16:57:56
1/1*3+1/3*5+……+1/99*101
=(1/2)*(2/1*3+2/3*5+……+2/99*101)
=(1/2)[(1/1-1/3)+(1/3-1/5)+……+(1/99-1/101)]
=(1/2)(1/1-1/101)
=50/101
看不明白,为什么有个分母1,不累赘吗?
原式=1/2 *『(1/1-1/3)+(1/3-1/5)+(1/5-......+(99/1-101/1)』
=1/2 * (1-101/1)
=50/101
1-1/3-1/5+1/3-1/5-1/7+1/5-1/7-1/9……+1/2003-1/2005-1/2007
1+1/2+1/3+1/4+1/5+1/6+1/7+1/8+......+1/100 = ?
1×1/2+2×1/3+3×1/4+4×1/5+5×1/6+……98×1/99+99×1/100
1/1×2×3+1/2×3×4+1/3×4×5···+1/98×99×100
1+1/2+1/3+.......+1/n=?
1×1/2+2×1/3+3×1/4+4×1/5+5×1/6+6×1/7+7×1/8+8×1/9+9×1/10
1/1*3+1/3*5+1/5*7+........+1/17+19
(1-1/2)(1-1/3)(1-1/4)(1-1/5).....(1-1/1000)
1+1/2+1/3+1/4...+1/n=?
初中一年级数学计算题:1/3+1/3×5+1/5×7+1/7×9+…+1/97×99+1/99×101=?怎么计算的?