(1÷0.1)÷(0.1÷0.2)÷(0.2÷0.3)……÷(0.8÷0.9)的简便算法

来源:百度知道 编辑:UC知道 时间:2024/06/14 17:18:48
必须要有过程,写的要清楚.

(1÷0.1)÷(0.1÷0.2)÷(0.2÷0.3)……÷(0.8÷0.9)
=10*2*3/2*4/3*.......*9/8(前一个分子和后一个分母约去)
=10*9=90

(1÷0.1)÷(0.1÷0.2)÷(0.2÷0.3)……÷(0.8÷0.9)=
(1÷0.1)*(0.2÷0.1)*(0.3÷0.2)……*(0.9÷0.8);
展开..分子分母可以抵消掉..
=0.9/0.1*0.1;
=90;

(1÷0.1)÷(0.1÷0.2)÷(0.2÷0.3)……÷(0.8÷0.9)的简便算法
(1÷0.1)÷(0.1÷0.2)÷(0.2÷0.3)……÷(0.8÷0.9)=
1÷0.1*0.2÷0.1*0.3÷0.2*0.4÷0.3*0.5÷0.4……÷0.8*0.9=
1÷0.1÷0.1*0.9=90
其实用分数来看更直接
(1÷0.1)÷(0.1÷0.2)÷(0.2÷0.3)……÷(0.8÷0.9)=
1/0.1*0.2/0.1*0.3/0.2*0.4/0.3……*0.9/0.8=90