数学题(化简求值)

来源:百度知道 编辑:UC知道 时间:2024/06/15 20:26:02
若a=1/2,b=1/3,求(3a²-ab)/(3a²+5ab-2b²)的值

(3a^2-ab)/(3a^2+5ab-2b^2)
=a(3a-b)/(3a-b)(a+2b)
=a/(a+2b)
=(1/2)/(1/2+2*1/3)
=(1/2)/(7/6)
=(1/2)*(6/7)
=3/7

(3a²-ab)/(3a²+5ab-2b²)=a(3a-b)/(3a-b)(a+2b)=a/a+2b
=1/2/(1/2+2*1/3)=3/7

=a(3a-b)/(3a-b)(a+2b)
=a/(a+2b)代入值为3/7

原式=a(3a-b)/((3a-b)*(3a+2b))=a/(3a+2b)
=1/2/(3*1/2+2*1/3)=3/13

原式=a(3a-b)/(3a-b)*(a+2b)=a/(a+2b)
余下的会做吧