一道初中的因式分解

来源:百度知道 编辑:UC知道 时间:2024/06/04 10:21:19
X^4-8XY^3+3X^3Y-6X^2Y^2

X^4-8XY^3+3X^3Y-6X^2Y^2
=x(x^3-8y^3+3x^2y-6xy2)
=x[(x-2y)(x^2+2xy+4y^2)+3xy(x-2y)]
=x(x-2y)(x^2+5xy+4y^2)
=x(x-2y)(x+y)(x+4y)

=X(X^3-8Y^3)+3X^2Y(X-2Y)
=X(X-2Y)(X^2+4XY+Y^2)+3X^2Y(X-2Y)
=(X-2Y)(X^3+4X^2Y+XY^2+3X^2Y)
=(X-2Y)(X^3+7X^2Y+XY^2)

路过,还真是麻烦,不过有人做出来,顶