1/3×1+1/4× 2+1/5× 3+…+1/2007×2005+1/2008×2006
来源:百度知道 编辑:UC知道 时间:2024/05/21 04:32:25
1/3×1+1/4× 2+1/5× 3+…+1/2007×2005+1/2008×2006
=1/2[(1-1/3)+(1/2-1/4)+(1/3-1/5)+………+(1/2005-1/2007)+(1/2006-1/2008)
=1/2[1+1/2-1/2007-1/2008]
然后就得自己慢慢算了,没有简便方法了
楼上的看错了,楼主又没写括号
1/(3×1)+1/(4× 2)+1/(5× 3)+…+1/(2007×2005)+1/(2008×2006)
=[(1/1-1/3)+(1/2-1/4)+(1/3-1/5)+.......+(1/2006-1/2008)]/2
=[1/1+1/2-1/2007-1/2008]/2
=1/2+1/4-1/4014-1/4016
(1+1/2+1/3+1/4)×
1+1/2+1+1/3+1+1/4+......+1/100=?
1/1+1/2+1/3+1/4+。。。。+1/N 是多少
1/1+1/2+1/3+1/4+......1/2002=?
1-1/2+1/3-1/4+........1/99-1/100
(1-1/2)(1-1/3)(1-1/4)(1-1/5).....(1-1/1000)
1/1*2+1/2*3+1/3*4+...+1/99*100
1/1*2+1/2*3+1/3*4+..........+1/2002*2003
1*(1/2)+2*(1/3)+3*(1/4)+...+99*(1/100)
1/1*2+1/2*3+1/3*4+......+1/9*10