solve a differential equation! In a hurry
来源:百度知道 编辑:UC知道 时间:2024/06/15 02:04:26
y''-2y'+y=e^t * t^-1
特解怎么求?是设 特解u= A* t*e^t*(In t- B), 然后带入求得常数ab 值得?
特解怎么求?是设 特解u= A* t*e^t*(In t- B), 然后带入求得常数ab 值得?
这个题推荐使用拉普拉斯变换进行求解
两边同时取拉普拉斯变化,再利用初始条件
求出Y=L(y)
在利用反变换求出y
应该学了吧
自己算算吧
先解对应齐次方程y''-2y'+y=0的解
它的解是y=C1e^t+C2te^t,c1,c2是2个常数
然后求出原方程的一个特解,再用特解加上齐次方程的解即可
但是特解我不会求,没学好
通解是y=C1e^t+C2te^t
特解是t*(lnt-1)*e^t
Please solve a problem for me
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