求助一道初一数学题，在线等

来源：百度知道 编辑：UC知道 时间：2024/06/04 04:15:24
用3 ， 4 ， -6 ， 10这四个数分别运用加减乘除或乘方、括号，使它的结果得24或-24，要两种算式
谢谢了！~~~~

3[10+4+(-6)]=24
10-4-3*(-6)=24
.......

-6/3=-2
-2*10=-20
-20-4=-24

-6*10=-60
-60/3=-20
4-(-20)=24

3×（4+10-6）=24
-3×（4+10-6）=-24

10-（3*（-6）+4）=24

（-6）*10/3-4=-24

我应该没算错吧~

1: 3 × (4 - 6 + 10)
2: 3 × ((4 - 6) + 10)
3: 3 × (4 - (6 - 10))
4: 3 × (4 + 10 - 6)
5: 3 × ((4 + 10) - 6)
6: 3 × (4 + (10 - 6))
7: 3 × 6 - 4 + 10
8: (3 × 6) - 4 + 10
9: (3 × 6 - 4) + 10
10: ((3 × 6) - 4) + 10
11: 3 × 6 -(4 - 10)
12: (3 × 6) - (4 - 10)
13: 3 × 6 + 10 - 4
14: (3 × 6) + 10 - 4
15: (3 × 6 + 10) - 4
16: ((3 × 6) + 10) - 4
17: 3 × 6 +(10 - 4)
18: (3 × 6) + (10 - 4)
19: 3 × (10 + 4 - 6)
20: 3 × ((10 + 4) - 6)
21: 3 × (10 + (4 - 6))
22: (3 × (10 - 4)) + 6
23: 3 × (10 - 4) + 6
24: 3 × (10 - 6 + 4)
25: 3 × ((10 - 6) + 4)
26: 3 × (10 - (6 - 4))
27: 4 + 6 ÷ 3 × 10