(sin50°(1+√3*tan10°)-cos20°)/(cos80°*√(1-cos20°))
来源:百度知道 编辑:UC知道 时间:2024/05/26 00:42:51
很急的
电脑上打出来的有点乱,你先抄到纸上再看吧
(sin50°(1+√3*tan10°)-cos20°)/(cos80°*√(1-cos20°))
=(sin50°(1+√3*sin10°/cos10°)-cos20°)/(cos80°*√(1-cos20°))
=(sin50°((cos10°+√3*sin10°)/cos10°)-cos20°)/(cos80°*√(2(sin10°)^2))
=(sin50°((1/2)cos10°+(√3/2)*sin10°)/((1/2)*cos10°)-cos20°)/(cos80°*√(2(sin10°)^2))
=(sin50°(sin30°*cos10°+cos30°*sin10°)/(1/2)*cos10°-cos20°)/((√2)cos80°*sin10°)
=(sin50°*sin40°/(1/2)*cos10°-cos20°)/((√2)sin10°*sin10°)
=(sin50°*cos50°/(1/2)*cos10°-cos20°)/((√2)sin10°*sin10°)
=((1/2)sin100°/(1/2)*cos10°-cos20°)/((√2)sin10°*sin10°)
=((1/2)sin80°/(1/2)*cos10°-cos20°)/((√2)sin10°*sin10°)
=((1/2)cos10/(1/2)*cos10°-cos20°)/((√2)sin10°sin10°)
=(1-cos20°)/((√2)sin10°sin10°)
=2(sin20°)^2/(√2)(sin20°)^2
=2/√2
=√2
sin50*(1+√3*tan 10)
sin50°(1+根号3×tan10°)的值??
(cot5°-tan5°)×(1-cos20°)/(3sin50°-√3×cos50°)=?
sin50度乘以(1+根号3乘以tan10度)等于?
sin50(1 根号3乘以tan10)要过程
求值sin50度(1+根号3tan1o度)=
〔2sin50°+sin10°(1+根号3再乘tan10°)〕*根号下2*sin80°的平方〕
((sin40+sin50(1+根号3*tan10))/sin70*根号(1+cos40)
sin10°sin30°sin50°sin70°=?
sin10°*sin40°+cos10°*sin50°