问一道超简单数学题

来源:百度知道 编辑:UC知道 时间:2024/05/11 16:35:40
现有 3 4 -6 10 四个数,用混合运算使其结果为24

应该怎么算?

(10+(-6)+4)*3=24

10-(-6*3)-4=24

(10+4-6)*3

1: 3 × (4 - 6 + 10)
2: 3 × ((4 - 6) + 10)
3: 3 × (4 - (6 - 10))
4: 3 × (4 + 10 - 6)
5: 3 × ((4 + 10) - 6)
6: 3 × (4 + (10 - 6))
7: 3 × 6 - 4 + 10
8: (3 × 6) - 4 + 10
9: (3 × 6 - 4) + 10
10: ((3 × 6) - 4) + 10
11: 3 × 6 -(4 - 10)
12: (3 × 6) - (4 - 10)
13: 3 × 6 + 10 - 4
14: (3 × 6) + 10 - 4
15: (3 × 6 + 10) - 4
16: ((3 × 6) + 10) - 4
17: 3 × 6 +(10 - 4)
18: (3 × 6) + (10 - 4)
19: 3 × (10 + 4 - 6)
20: 3 × ((10 + 4) - 6)
21: 3 × (10 + (4 - 6))
22: (3 × (10 - 4)) + 6
23: 3 × (10 - 4) + 6
24: 3 × (10 - 6 + 4)
25: 3 × ((10 - 6) + 4)
26: 3 × (10 - (6 - 4))
27: 4 + 6 ÷ 3 × 10
28: 4 + (6 ÷ 3) × 10
29: 4 + (6 ÷ 3 × 10)
30: 4 + ((6 ÷ 3) × 10)
31: 4 + (6 ÷ (3 ÷ 10))
32: 4 + 6 ÷(3 ÷ 10)
33: 4 + 6 × 10 ÷ 3
34: 4 + (6 × 10) ÷ 3
35: 4 +