函数问题，急!

答案：x=<-1或x>=2
解：f(x)=mx^2-mx-1<5-m
m(x^2-x+1)<6
m<6/[(x-1/2)^2+3/4]
因为m属于[-2,2]
所以-2=<6/[(x-1/2)^2+3/4]=<2
-2(x^2-x+1)=<6
或6<2(x^2-x+1)
得x^2-x+1>=-3
或x^2-x+1>=3
x^2-x-2>=0
(x-2)(x+1)>=0
x=<-1或x>=2

f(x)<5-m
-2x^2+2x-1＜5+2
2x^2-2x-1＜3