高一数学对数题，谁来帮帮忙

log(ab)lg(a/b)^2
=log(ab)(log a^2 - log b^2)
=log(ab+a^2)-log(ab+b^2)
=log((ab+a^2)/(ab+b^2))
=log(a/b)
=log a - log b

从方程得出,
log a + log b =2
log a * log b =1/2
(log a - log b)^2 =(log a +log b)^2-4*log a * log b
=4-2=2
所以log a - log b = 根号2
所以log(ab)log(a/b)^2 = 根号2

lg(ab)(lga/b)^2
=(lga+lgb)(lga-lgb)^2
=(lga+lgb)((lga)^2+(lgb)^2-2lgalgb)
=(lga+lgb)((lga+lgb)^2-4lgalgb)
=2*(2^2-4/2)
=4

上面的回答已经很正确了，不需要我说什么了