帮忙解个数学题.

f(x)+f(1-x)=1/(2^x+根号2)+1/[2^(1-x)+根号2]
=1/(2^x+根号2)+2^x/[2+根号2*2^x]
=(1+2^x/根号2)*[1/(2^x+根号2)]
=[(2^x+根号2)/根号2]*[1/(2^x+根号2)]
=1/根号2
=根号2/2

f(-5)+f(-4)+...+f(0)+...+f(5)+f(6)
=[f(-5)+f(6)]+[f(-4)+f(5)]+...+[f(0)+f(1)]
=根号2/2*6
=根号2*3

370116 回答和我的一样，答案就是3根号2
过程不懂可以问我