1/(1+√2)+1/(√2+√3)+1/(√3+√4)+……1/(√2007+√2008)
来源:百度知道 编辑:UC知道 时间:2024/06/14 15:21:03
1/(1+√2)=[1*(√2-1)]/[(√2-1)*(√2+1)=√2-1
1/(√2+√3)=....=√3-√2
......
......
1/(√2007+√2008)=√2008-√2007
==>1/(1+√2)+1/(√2+√3)+1/(√3+√4)+……1/(√2007+√2008)=√2008-1
都先分母有理化,则原式变成
-(1-√2)-(√2-√3)-....-(√2007-√2008)=-1+√2008
「2008一1
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